Anybody else agree that there is not a correct answer to this question they're all Z or E it is necessary that on carbon of the double bond must have two identical functional groups (or two hydrogens) in order for the alkene to be designated E or Z none of the carbons in any of the molecules presented possess this feature, this said achiever is deffinatly worth the money

Also on Q 52 test 3 of achiever did they forget that there are 3 molecules of water being broken down or am i forgetting something?

Also on Q 52 test 3 of achiever did they forget that there are 3 molecules of water being broken down or am i forgetting something?
They got me on Q52 as well, you have to notice that two of the H2O molecules are used up in the Fe solid reaction and only one gets broken down via that third rxn.

Anybody else agree that there is not a correct answer to this question they're all Z or E it is necessary that on carbon of the double bond must have two identical functional groups (or two hydrogens) in order for the alkene to be designated E or Z none of the carbons in any of the molecules presented possess this feature, this said achiever is deffinatly worth the money

This was my understanding as well. Obviously if one of the carbons forming the double bond had the two same substituents then E or Z naming isn't applicable but I think that E/Z is still applicable if both carbons have the same substituent. BrCH=CHBr with Br's one same side of the double bond is still Z, right?

Edit: Nevermind, this would fall under the cis/trans category. DAT Achiever is the king. :o