when a sample was burned in a bomb calorimeter containng 1 Kg of water, the temp of the water increased 1 Celsius. If the heat capcity of system was 0 KJ/K and the specific heat of water is 4.18 J/Kg, how much heat was involved?


the correct answer is 4.18 KJ which I confimed by q = 1 * 1 * 4.18

but I don't get why it mentioned heat capcity of system was 0 ? would that make q = 0 then so no heat is inovled?

in a bomb calorimeter, no heat enters or leaves the system. thus the SYSTEM has a q of zero. the steel, the liquid all do exchange heat with the system, and so have q's not equal to zero. technical term put in there just to confuse.