Ocean5
09-08-2007, 09:50 AM
A ski-boat can travel 20 mph in calm water. On a river it can travel 45 miles with the current in the same time it can travel 27 miles against the currect. What is the current's rate in m/h?
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View Full Version : QR- rate problem Ocean5 09-08-2007, 09:50 AM A ski-boat can travel 20 mph in calm water. On a river it can travel 45 miles with the current in the same time it can travel 27 miles against the currect. What is the current's rate in m/h? dmddream 09-08-2007, 09:59 AM A ski-boat can travel 20 mph in calm water. On a river it can travel 45 miles with the current in the same time it can travel 27 miles against the currect. What is the current's rate in m/h? are 45 and 27 in miles or miles per hour? Ocean5 09-08-2007, 10:04 AM are 45 and 27 in miles or miles per hour? This is all the problem gives us. I guess the main point to consider is that both are at the same time. 45 w/t the current happens in the same time as 27 against the current. dmddream 09-08-2007, 10:25 AM is 5.56 one of the answers Ocean5 09-08-2007, 10:31 AM is 5.56 one of the answers Ohh about the answers. These are only choices: - 4 - 5 - 13 1/3 - 18 - 80 Streetwolf 09-08-2007, 10:31 AM Boat's speed is 20mph. Current's speed is x mph. So with the current the boat goes (20+x)mph. Against the current the boat goes (20-x)mph. R x T = D Boat goes 45 miles with the current: (20+x)*t = 45 Boat goes 27 miles against the current: (20-x)*t = 27 So we have a system of equations: 20t + xt = 45 20t - xt = 27 Add the two: 40t + 0 = 72 t = 9/5 = 1.8 So plug that into one of the above equations: (20+x)(9/5) = 45 20+x = 45(5/9) = 25 20+x = 25 x = 5 Current is 5 mph. Plug in this answer to confirm. Ocean5 09-08-2007, 10:43 AM Boat's speed is 20mph. Current's speed is x mph. So with the current the boat goes (20+x)mph. Against the current the boat goes (20-x)mph. R x T = D Boat goes 45 miles with the current: (20+x)*t = 45 Boat goes 27 miles against the current: (20-x)*t = 27 So we have a system of equations: 20t + xt = 45 20t - xt = 27 Add the two: 40t + 0 = 72 t = 9/5 = 1.8 So plug that into one of the above equations: (20+x)(9/5) = 45 20+x = 45(5/9) = 25 20+x = 25 x = 5 Current is 5 mph. Plug in this answer to confirm. :thumbup: Thank You. REH 09-08-2007, 11:10 AM Ocean5, These are good problems that you're posting. Where are you finding them? REH. Ocean5 09-08-2007, 11:24 AM Ocean5, These are good problems that you're posting. Where are you finding them? REH. Over time I have recoreded some problems that I had a harder time solving them, so I get them from my notebook. Sorry that I haven't recorded their original source. However, they are from all sources that we normally use to prepare for DAT. I'm glad that you find them helpful. |