gopher341238
07-21-2008, 08:48 PM
Here is the Kaplan Question...
http://img105.imageshack.us/img105/8494/elevationet3.th.gif (http://img105.imageshack.us/my.php?image=elevationet3.gif)
I thought you had to take into account the Van't Hoff Factor.. shouldn't it be 3 for Na2SO4.. and then the answer should be ~ 100.75
I-Baby
07-21-2008, 09:00 PM
Here is the Kaplan Question...
http://img105.imageshack.us/img105/8494/elevationet3.th.gif (http://img105.imageshack.us/my.php?image=elevationet3.gif)
I thought you had to take into account the Van't Hoff Factor.. shouldn't it be 3 for Na2SO4.. and then the answer should be ~ 100.75
Looks like a mistake to me unless there is something that we are both missing. The only time the Van't Hoff factor would not be included was if the solute was non-ionic and doesn't dissociate (i=1, like C6H12O6). If I'm not mistaken, Na2SO4 is ionic and would dissociate into 3 ions like you said.
gopher341238
07-21-2008, 09:02 PM
Thanks I-Baby. I assumed it was a mistake and I have the same understanding as you about van't hoff factor not mattering for something like glucose. I just wanted to run it by a fellow SDN'er to make sure I wasn't missing something obvious. Thanks again.
lichweiss
07-21-2008, 09:04 PM
Here is the Kaplan Question...
http://img105.imageshack.us/img105/8494/elevationet3.th.gif (http://img105.imageshack.us/my.php?image=elevationet3.gif)
I thought you had to take into account the Van't Hoff Factor.. shouldn't it be 3 for Na2SO4.. and then the answer should be ~ 100.75
yeah you have to consider the 3.
so the answer should be 100.768C
I-Baby
07-21-2008, 09:13 PM
Thanks I-Baby. I assumed it was a mistake and I have the same understanding as you about van't hoff factor not mattering for something like glucose. I just wanted to run it by a fellow SDN'er to make sure I wasn't missing something obvious. Thanks again.
No problem. Actually, seeing that reinforced the concept for me so I should say thank you. GL with your studying!
Contach
07-22-2008, 01:56 AM
what is the Vont Hoff Factor?
Thanks.