When adding Br2/ hv doesnt the H add to the least subsitiuted C? I dont know how to upload the picture but I dont understand why A is the right answer

The reaction X2 and light is the halogenation of an alkane reaction. Bromine is selective for the position that gives it the most stable radical. The carbon that is adjacent to the double bond is the most stable position making it the most stable radical.

Hope that helpss

Br2/hv goes to eh most substitued cabron. it is markinkoff. It becomes the least subsituted with ROOR.

Br/light doesn't go to the most sub carbon, it wants to go to the allylic carbon.

Keep it as simple as that.

Br/light doesn't go to the most sub carbon, it wants to go to the allylic carbon.

Keep it as simple as that.

That is how I learned it. Br2/hv and NBS both add Br to the allylic position...HBr works with Markovnikov's rule which is adding Br to the most substituted carbon, and HBr/ROOR (peroxide) add's Anti-markovnikov...