Lazerous
08-07-2008, 03:47 PM
Is it spontaneous? As in does it have a negative delta G?
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View Full Version : Initiation step of radical formation? Lazerous 08-07-2008, 03:47 PM Is it spontaneous? As in does it have a negative delta G? jdent 08-07-2008, 03:59 PM Is it spontaneous? As in does it have a negative delta G? is it spontaneous no you need somes ort of a catalyst to start off the reaction. And by the way -delta G means spontaneous Lazerous 08-07-2008, 04:04 PM is it spontaneous no you need somes ort of a catalyst to start off the reaction. And by the way -delta G means spontaneous Exactly! That's what I though except destroyer question 51 says it IS spontaneous and so it has a delta G< 0. So how would you explain that? jdent 08-07-2008, 04:09 PM Exactly! That's what I though except destroyer question 51 says it IS spontaneous and so it has a delta G< 0. So how would you explain that? Ok now i see what you are saying getting teh right answer to that question is easy we know S will be positive an dthat H will also be positive. This reaction will only be spontaneous at high temperatures, namelessly the hv we put in it could be that Dr.Romano meant that and just thought it was obvious, but in general H S positive is only spontaneous at high temperatures! hope that helps. |