Hey math lovers, doing some engineering with my dad for a project and need some help with this equation.

12= sin[90-(x/2)]tan[x/2]

Please solve for X.

I'll check your answer with mine.

12=sin[90-(x/2)] tan [x/2] , sin [90-(x/2)]=-cos (x/2)
==> 12= -cos (x/2) tan [x/2]= -sin (x/2) no answer for x. always -1<sin a<1

12=sin[90-(x/2)] tan [x/2] , sin [90-(x/2)]=-cos (x/2)
==> 12= -cos (x/2) tan [x/2]= -sin (x/2) no answer for x. always -1<sin a<1

Agreed except I get sin(x/2) = 12, not -sin.

12=sin[90-(x/2)] tan [x/2] , sin [90-(x/2)]=-cos (x/2)
==> 12= -cos (x/2) tan [x/2]= -sin (x/2) no answer for x. always -1<sin a<1

what???
what's the "," comma on the first line and where did 12 go?