purplepanda
05-02-2009, 11:49 PM
nevermind, found a good post..sorry!
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View Full Version : Log without calculator? purplepanda 05-02-2009, 11:49 PM nevermind, found a good post..sorry! iwannabadentist 05-02-2009, 11:56 PM if [OH] = 2.0 x 10^-4, then u can say pOH = 4 - log 2 = 3.7 you should try to memorize some simple logs, at least 1-5: log 1 = 0 log 2 = 0.3 log 3 = 0.5 log 4 = 0.6 log 5 = 0.7 log 6 = 0.8 i just memorized it. its easy for 3-6, you just add 2 and put a decimal in front. log1 = 0 is also easy to memorize. hope that helps |