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 11-17-2010, 07:18 PM #1 Junior Member   Status Pre-Medical Join Date: May 2010 Posts: 14 friction problem SDN Members don't see this ad. (About Ads) Hey guys, help needed, here goes A meteor with a mass = 1Kg moving at 20km/s collides with jupiter's atmosphere. the meteor penetrates 100 km into the atmosphere and dsintegrates. What is the average force on the meteor once it enters Jupiter's atmosphere (ignore gravity)? a) 2*10^3 N b) 4*10^3 N c) 8*10^3 N d) 2*10^5 N thank you
 11-17-2010, 07:38 PM #2 Senior Member   Join Date: Sep 2010 Posts: 134 A?
 11-17-2010, 07:51 PM #3 Junior Member   Status Pre-Medical Join Date: May 2010 Posts: 14 that's correct, But i don't get it 1/2mv^2= F*d 1/2 * 1 * (20)^2 = F * 100km 200 = F* 100km F= 200/100 F= 2N what am I doing wrong????
 11-17-2010, 07:57 PM #4 Transform and Transcend     Status: Pre-Medical Join Date: Jan 2008 Location: Limbo Posts: 1,264 Convert Km to m in both the velocity and the displacement.
 11-17-2010, 08:06 PM #5 Junior Member   Status Pre-Medical Join Date: May 2010 Posts: 14 DUH!!!! I AM SO RETARDED! thank u so much
 11-18-2010, 10:22 AM #6 Transform and Transcend     Status: Pre-Medical Join Date: Jan 2008 Location: Limbo Posts: 1,264 Don't worry about it haha. That has happened to me about 1 million times.
 06-01-2012, 10:19 AM #7 New Member   Status Pre-Medical Join Date: Jun 2012 Posts: 1 hey I know this was posted a while back, but I am hoping someone can clarify this problem a little for me. I thought that you would use the equation Fdcos(theta) and cos of 0 is just one so then I thought this was set to equal the change in kinetic energy plus the change in potential energy so it would be F*d = delta K + delta U....how come above you just did F*d = delta K...where did the change of potential energy go? thanks!
08-02-2012, 02:34 PM   #8
New Member

Status Pre-Medical
Join Date: May 2011
Posts: 4

Quote:
 Originally Posted by panda2queen hey I know this was posted a while back, but I am hoping someone can clarify this problem a little for me. I thought that you would use the equation Fdcos(theta) and cos of 0 is just one so then I thought this was set to equal the change in kinetic energy plus the change in potential energy so it would be F*d = delta K + delta U....how come above you just did F*d = delta K...where did the change of potential energy go? thanks!
the question says to ignore gravitational force

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