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#1 |
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Junior Member
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A meteor with a mass = 1Kg moving at 20km/s collides with jupiter's atmosphere. the meteor penetrates 100 km into the atmosphere and dsintegrates. What is the average force on the meteor once it enters Jupiter's atmosphere (ignore gravity)? a) 2*10^3 N b) 4*10^3 N c) 8*10^3 N d) 2*10^5 N thank you |
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#2 |
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Senior Member
Join Date: Sep 2010
Posts: 134
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A?
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#3 |
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Junior Member
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that's correct, But i don't get it
1/2mv^2= F*d 1/2 * 1 * (20)^2 = F * 100km 200 = F* 100km F= 200/100 F= 2N what am I doing wrong???? |
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#4 |
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Transform and Transcend
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Convert Km to m in both the velocity and the displacement.
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#5 |
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Junior Member
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DUH!!!! I AM SO RETARDED! thank u so much
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#6 |
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Transform and Transcend
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Don't worry about it haha. That has happened to me about 1 million times.
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#7 |
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New Member
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hey I know this was posted a while back, but I am hoping someone can clarify this problem a little for me. I thought that you would use the equation Fdcos(theta) and cos of 0 is just one so then I thought this was set to equal the change in kinetic energy plus the change in potential energy so it would be F*d = delta K + delta U....how come above you just did F*d = delta K...where did the change of potential energy go?
thanks! |
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#8 | |
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New Member
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Quote:
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