Student Doctor Network Forums Translation Motion Eq. Derivation
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 07-06-2012, 04:49 PM #1 Junior Member   Status Pre-Medical Join Date: Mar 2012 Posts: 7 Translation Motion Eq. Derivation SDN Members don't see this ad. (About Ads) How is the following translational motion equation derived? vx2 = vo2 + 2axΔx Last edited by soccatrini08; 07-06-2012 at 06:48 PM.
 07-06-2012, 07:31 PM #2 Junior Member   Status Pre-Medical Join Date: Mar 2012 Posts: 7 Never mind I figured it out.
 07-06-2012, 07:56 PM #3 1K Member     Status: Pre-Medical Join Date: Dec 2009 Location: Where the rain grows Posts: 1,832 For anyone who has read the question but has not figured out how: Δx= V0.t+at^2/2 and V=V0+at From the second equation, t=(V-V0)/a, plug that instead of t in the first one, simplify and you'll get the formula above.

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