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Old 08-18-2005, 10:49 PM   #1
Denro
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Default math question #2


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What is the largest number from a series of four consecutive negative integers where the sum of the two smallest integers is -17?



A. -14
B. -12
C. -10
D. -8
E. -6

I always see these types of problems.. is there a certain formula that works best on these problems.. thanks.. and Ecoli thanks for solving the other one..
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Old 08-18-2005, 11:17 PM   #2
rals
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well if they're all consecutive, the two smallest numbers must be consecutive too. so that's -9 and -8. if these are the two smallest of four, the other two are -7 and and -6.

so the answer is -6.
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Old 08-19-2005, 02:05 AM   #3
786mine
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I didn't quite get the question. could someone rephrase it please. thank you.
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Old 08-19-2005, 10:01 AM   #4
dentalengineer
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ignor negative integer, deal with the problem as they are postive integers:

Let x = The First Consecutive Number
x+1 = the second
x+2 = the third
x+3 = the fourth

it says sum of the samllest consecutive numbers is -17

so x+x+1= -17 therfore x= -9 ( the first integer number)

the smallest integer number( the fourth one) after you plug the x is -6
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