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| DAT Discussions Discuss study tips and resources to excel on the Dental Admissions Test. |
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#1 |
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Member
Join Date: Mar 2005
Posts: 39
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What is the largest number from a series of four consecutive negative integers where the sum of the two smallest integers is -17?
A. -14 B. -12 C. -10 D. -8 E. -6 I always see these types of problems.. is there a certain formula that works best on these problems.. thanks.. and Ecoli thanks for solving the other one.. |
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#2 |
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Member
Join Date: Jul 2005
Posts: 343
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well if they're all consecutive, the two smallest numbers must be consecutive too. so that's -9 and -8. if these are the two smallest of four, the other two are -7 and and -6.
so the answer is -6. |
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#3 |
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"Baby Bear"
Join Date: Mar 2005
Posts: 302
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I didn't quite get the question. could someone rephrase it please. thank you.
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#4 |
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Member
Join Date: May 2005
Location: Manhattan
Posts: 9
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ignor negative integer, deal with the problem as they are postive integers:
Let x = The First Consecutive Number x+1 = the second x+2 = the third x+3 = the fourth it says sum of the samllest consecutive numbers is -17 so x+x+1= -17 therfore x= -9 ( the first integer number) the smallest integer number( the fourth one) after you plug the x is -6 |
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