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If upright, it is ALWAYS virtual? If upside down, it is ALWAYS real?

if so, this will make life a lot easier lol

here's hoping.

Yeah, virtual is upright, real is inverted. It deals with the equation
m = -hi/ho = -di/do

Originally Posted by pfaction

Yeah, virtual is upright, real is inverted. It deals with the equation
m = -hi/ho = -di/do

wait about in a double lens system where do can be negative and di can be positive.

Originally Posted by chiddler

wait about in a double lens system where do can be negative and di can be positive.

The signs are relative to each other, so I don't think it would matter.

Originally Posted by chiddler

If upright, it is ALWAYS virtual? If upside down, it is ALWAYS real?

if so, this will make life a lot easier lol

here's hoping.

Thought more about this and it does make it simpler for the MCAT. Any answer choices that are "real and upright" or "virtual and inverted" are wrong!

Originally Posted by MedPR

Thought more about this and it does make it simpler for the MCAT. Any answer choices that are "real and upright" or "virtual and inverted" are wrong!

EK physics #999.

One real image inverted by another converging lens to produce an upright, real image.

Originally Posted by chiddler

EK physics #999.

One real image inverted by another converging lens to produce an upright, real image.

its true for a single lens image

once you include another lens it no longer applies to the FINAL image but DOES apply to the intermediate image


ex
converging lens w/ a diverging lens

Originally Posted by MrNeuro

its true for a single lens image

once you include another lens it no longer applies to the FINAL image but DOES apply to the intermediate image


ex
converging lens w/ a diverging lens

yeah i know this.

So lets make some generalizations:

A converging lens (object outside focal) + diverging lens ---> Inverted, virtual image. Always.
A converging lens (inside focal) + diverging ---> upright virtual

A converging (outside focal) + converging (outside focal) ---> Upright real
A converging (outside focal) + converging (inside focal) ----> i suppose this depends on how close the image is to the second lens. Right?

A converging (inside focal) + converging (outside focal) ---> depends
And converging (inside) + converging (inside) ---> virtual upright.

Originally Posted by MrNeuro

its true for a single lens image

once you include another lens it no longer applies to the FINAL image but DOES apply to the intermediate image


ex
converging lens w/ a diverging lens

It always applies as long as you remember that the second lens effects (upright/virtual, real/inverted, etc) are relative to the second object (first image) and not the first object.

Originally Posted by chiddler

yeah i know this.

So lets make some generalizations:

A converging lens (object outside focal) + diverging lens ---> Inverted, virtual image. Always.
A converging lens (inside focal) + diverging ---> upright virtual

A converging (outside focal) + converging (outside focal) ---> Upright real
A converging (outside focal) + converging (inside focal) ----> i suppose this depends on how close the image is to the second lens. Right?

A converging (inside focal) + converging (outside focal) ---> depends
And converging (inside) + converging (inside) ---> virtual upright.

does anybody know how i figured this out? i can't remember =/

nvm i got it :-3