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 05-03-2012, 12:29 AM #1 Junior Member   Status: Dental Student Join Date: Apr 2012 Posts: 19 DAT Practice Question Help SDN Members don't see this ad. (About Ads) Hello everyone, I need some help here. I'm not sure how to solve this problem. "If ab=2 bc=3 cd=6 then ad=?" Not sure how to go about solving this problem. I think I'll feel stupid once someone shows me how simple it is but I have no idea how to approach it at the moment.
 05-03-2012, 12:53 AM #2 YOSH!!~     Status: Dental Student Join Date: Apr 2010 Location: Grand Line Posts: 640 I'm not sure if it's the easiest way but you can rearrange for a single variable and than substitute that into another equation. Rinse and repeat til you get your answer than you can back track and find the value of each variable. There is probably a quicker way via subtracting/adding equations.
 05-03-2012, 06:49 AM #3 Nothing to do here     Status: Dental Student Join Date: Jul 2010 Posts: 740 Is this question only assuming integers?
05-03-2012, 09:35 AM   #4
Member

Status: Pre-Dental
Join Date: Feb 2012
Posts: 59

Quote:
 Originally Posted by PaulC Hello everyone, I need some help here. I'm not sure how to solve this problem. "If ab=2 bc=3 cd=6 then ad=?" Not sure how to go about solving this problem. I think I'll feel stupid once someone shows me how simple it is but I have no idea how to approach it at the moment.
I'm going to go ahead and take a stab at this, sorry if I just completely get it wrong.

a*b = 2, so I'm going to assume integers to begin with, so I'm assuming A = 2 and B = 1
b*c = 3, so B = 1 is working out, therefore C must be 3
c*d = 6, so if C = 3, then D should equal 2...

a*d = 4, because a = 2 and d = 2 ?

It would be nice if we were able to see the actual answer and/or the multiple choice possibilities!

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Edit: Tried it a different way, got the same answer (just follow the numbers in order...)

Last edited by Worried12345; 05-03-2012 at 09:46 AM. Reason: added picture

 05-03-2012, 04:01 PM #5 Member   Status: Pre-Dental Join Date: Mar 2012 Posts: 90 ab=2 bc=3 cd=6 My answer is similar to top one. leave bc=3 as is but b=2/a...(1) from ab=2 and c=6/d...(2) from cd=6 now substitute (1) and (2) into bc=3 (2/a)(6/d)=3 (12/ad)=3 12= 3ad 4=ad
05-03-2012, 06:22 PM   #6
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Status: Pre-Medical
Join Date: Dec 2007
Posts: 390

Quote:
 Originally Posted by PaulC Hello everyone, I need some help here. I'm not sure how to solve this problem. "If ab=2 bc=3 cd=6 then ad=?" Not sure how to go about solving this problem. I think I'll feel stupid once someone shows me how simple it is but I have no idea how to approach it at the moment.
you want to solve for AD, so i will attempt to find what i can substitute for A and D, reducing to once common term.

I. ab=2, therefore a= 2/b
II. bc=3 therefore b = 3/c
III. cd=6, therefroe d= 6/c

now i can substitue for AD
( 2/b ) ( 6/c) =?

To come up with like terms, i will substitute for my previous vale of b, which could also be done in the opposite manner substituting for c instead in equation II.

( 2/ [3/c] ) ( 6/c) =?

( 2c/3 ) ( 6/c ) = ?

c's cancel, and you have (2/3) (6) = 12/3 = 4

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