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#1 |
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Senior Member
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so C for Charge ...more of a charge is MORE basic or LESS basic? A - atom size - bigger is MORE basic or LESS basic? etc...for the rest? Im getting all of the more complicated problems correct but missing simpler ranking questions like this
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#2 |
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Senior Member
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Charge- more negatively charged species are more basic
Atom- Large and/or more electronegative the atom with a negative charge, the more stable it is. More stable would mean a weaker base. Note that size is more important, so first consider the size. If the species are in the same row, then you will have to consider the electronegativity. However, if they are in the same column, then you can just consider the atom size (with the larger anions being more stable, so weaker bases). Resonance- more resonance structure means more stable, so weaker base Dipole induction- EWG near an atom with a negative charge stabilizes the molecule, so weaker base Orbitals: sp3 is more basic than sp2 which is more basic than sp. sp is the most stable, hence the weakest base. Hope this helps! |
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#3 |
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Senior Member
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Which of the following is the least acidic
55% A: [Correct] CH4 2% B: PH3 8% C: SH2 23% D: NH3 12% E: [Yours] H2O Explanation To determine the acidity of these structures, we should examine the stability of their conjugate bases. Of the conjugate bases, CH−3 is the least stable; thus, CH4 would be the least acidic. ^^in reference to the above problem....so if we're looking for the least acidic, we're looking for the one that would give the strongest conjugate base and therefore the least stable one? and also, so CH3- is a stronger base/less stable than OH- ?? also do the same rules apply to acids? less stable = stronger acid and more stable = weaker acid? Are these statements true? · Strongest conjugate acid gives weakest conjugate base. Strongest conjugate base gives weakest conjugate acid. Last edited by Member 8586; 05-25-2012 at 07:17 PM. |
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#4 |
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Member
Join Date: Mar 2012
Posts: 48
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Yes. It's the same relationship. Think of the formula
HA ---> A- and H+ HA= acid. A-=conjugate base. H+=proton So the more stable A- is, the more WEAK of a base and the STRONGER HA is. If A- is unstable, then it is a STRONG base and HA is a WEAK acid In this problems case, I believe it's just a matter of the atom the charge would be on. If you deprotonated the compounds you could see Carbon is the least electronegative making it unstable because C can't handle (-) as well as O,P,N or S I believe in Chad's lecture, he describes CARDIO as to find the strongest acid. So if you were trying to find the least acidic, you would also be looking for the most basic. So just switch the rules and look for the opposite, if that makes sense. Last edited by Kratoz24x; 05-25-2012 at 07:23 PM. Reason: Clarifying |
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#5 |
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Senior Member
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"also do the same rules apply to acids? less stable = stronger acid and more stable = weaker acid?
Are these statements true? · Strongest conjugate acid gives weakest conjugate base. Strongest conjugate base gives weakest conjugate acid." Correct.. The person above me described it correctly. C is the least electronegative, so it's the most basic...which means its conjugate acid is the weakest. OH- would be a weaker base because of electronegativity |
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#6 | ||
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Senior Member
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Quote:
Quote:
so this is what ive gathered after fully going through your explanations (bolded constitutes a stronger base)..please correct me if any of it is wrong:
or kinda in chart form: STRONGEST BASE:
STRONGEST ACID:
Last edited by Member 8586; 05-28-2012 at 09:50 AM. |
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#7 | |
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Senior Member
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Quote:
Based on what Chad said, atomic size takes preference, but he said that can be used when all the elements you are comparing are in the same column (as you go down the column, size increases and larger anions are more stable). If you are comparing elements in the same row, he said to move on to electronegativity. In this case some are in the same column and some are not, I am guessing it's pretty hard to determine the atomic size, so electronegativity would be a better/easier comparison. |
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#8 | |
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Senior Member
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Quote:
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#9 |
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Senior Member
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#10 |
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Senior Member
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I always learned that you never compare acids, you only compare conjugate bases to determine acidity. Once you have all of your conjugate bases, you can use CARDIO (wish our professor used that) to determine which of the compounds can BEST stabilize that negative charge. More negative charges are more basic, larger atoms can distribute the negative charge more, more electronegative atoms can better stabilize the charge, more resonance will stabilize the charge, dipole-induction will help stabilize the charge, and more s-character will help stabilize the charge too. The better it can stabilize the negative charge, the more likely the acid of that conjugate base will dissociate, hence a stronger acid. If it isn't stable, then it's a stronger base.
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#11 | |
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Senior Member
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so then wouldnt H2O's conjugate base be OH-? or they all have a negative charge because we're taking the conjugate base?
also, i dont know if you noticed the little summary i typed in bc i edited the post...can you verify if thats right? Quote:
and if youre asked for least or most basic straight up - then you can just use CARDIO? |
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#12 |
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Senior Member
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No matter what they ask, you always find the conjugate base. The most basic is the least acidic, and the most acidic is the least basic, right? Just take off a proton, even if it looks like a ridiculous unlikely compound. For example, CH4, conjugate base is CH3(-). This thing does not look stable at all, so I think it'll be more basic compared to something like H2C=CH(-), where the double bond can better handle the negative charge.
No matter acid or base, don't assume anything. Always get the conjugate base, then arrange them in order of stability using CARDIO. The most stable conjugate base is the most acidic, the least stable conjugate base is the least acidic (and hence most basic). |
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