Conceptual pressure question

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

SaintJude

Full Member
10+ Year Member
Joined
Jan 4, 2012
Messages
1,479
Reaction score
5
View attachment Picture 20.png

EK Can someone explain?

Edit: EK's explnation: The fluid at A, C, D is at atmospheric pressure. The fluid at B is at atmospheric pressure plus "pgh"[the elevation head].

Members don't see this ad.
 
Last edited:
Well, A and D are both just atmospheric pressure, so those are out. If I'm not mistaken, since fluids are incompressible, any fluid at a particular depth will have equivalent pressure as well. So, I don't know between B and C?

B seems like it would have higher pressure because there is taller column of water above it, but C is in a smaller volume (a little pipe vs the huge beaker). Although, according to my ruler, point C is actually slightly lower than point B. So C? :)
 
Yeah, I follow you: A& D are immediately out. I myself have trouble distinguishing between B& C.
 
C is slightly lower. The shape of the container around it does not matter.
 
Members don't see this ad :)
No, the answer is B. And I think point C and point B were intended to be shown at equal heights...
 
No, the answer is B. And I think point C and point B were intended to be shown at equal heights...


If B is the answer then the only explanation I can think of (why it's not C) is that there is a taller column of water above B than C. Pressure = patm+pgh. hB is greater than hC.
 
Or the pressure in the tube is lower since the water is moving there and the pressure is lower due to Bernoulli.
 
Or the pressure in the tube is lower since the water is moving there and the pressure is lower due to Bernoulli.

Yea that too. I have a feeling I'm going to be wrong, but I'm going to say that velocity at C is higher than velocity at B (continuity) and higher velocity = lower pressure (bernoulli)? :)
 
Yea that too. I have a feeling I'm going to be wrong, but I'm going to say that velocity at C is higher than velocity at B (continuity) and higher velocity = lower pressure (bernoulli)? :)

That would be it, you're correct this time.

To make that assessment, you want B and C to be equally high. If B is higher than C, you'll have to do the math with the exact pressures, velocities, fluid, etc. to determine which one is lower.
 
can you please elaborate on this a little more?

You can consider the big reservoir as a very wide pipe and the syphon as a much smaller pipe. You have (supposedly) laminar flow and the points are at the same height. Apply Bernoulli's law and you'll have faster velocity of movement and lower pressure in the tube with lower area.
 
.5*density *velocity^2

This is a way of expressing Bernoulli. Air over a wing flows faster than the air flowing on the bottom surface. So the dynamic head is higher on top than on the bottom. In an ideal situation the total pressure is constant, which means the top of the wing sees a lower static pressure than the bottom. So over the area of the wing the bottom gets pushed on more than the top, and lift is generated.
 
Top