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So there's a question on their FL 3:
Ca(OH)2 has approximately the same Ksp as CaSO4. Which of them has the greater solubility in terms of mol L-1?
The answer ended up being Ca(OH)2. I don't get why CaSO4 doesn't have a higher molar solubility though.
Wouldn't the molar solubility of CaSO4 simply be the square root of Ksp, while for Ca(OH)2 it's the cubed root of 1/4?
So wouldn't CaSO4 "have the higher number" per say, so it has a higher molar solubility?
Ca(OH)2 has approximately the same Ksp as CaSO4. Which of them has the greater solubility in terms of mol L-1?
The answer ended up being Ca(OH)2. I don't get why CaSO4 doesn't have a higher molar solubility though.
Wouldn't the molar solubility of CaSO4 simply be the square root of Ksp, while for Ca(OH)2 it's the cubed root of 1/4?
So wouldn't CaSO4 "have the higher number" per say, so it has a higher molar solubility?