hard normality question help

[Smooth Operater]

given that following rxn

HCl + Ba(OH)2 --> BaCl2 + H2O. What volume of 1 N of HCK is required to react completely w/ 10 mL of 1 N Ba(OH)2?

the correct answer is 10 mL. But I am not sure why I don't get this answer.

I went 10 mL * 1N * 2/1 = 20 mL.

What's the correct way to think about this Q? Thanks!

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[Manyak222]

lol the answer is given to you, all the work is done. all Happy has to do is send it home. why would you multiply by 2?

given that following rxn

HCl + Ba(OH)2 --> BaCl2 + H2O. What volume of 1 N of HCK is required to react completely w/ 10 mL of 1 N Ba(OH)2?

the correct answer is 10 mL. But I am not sure why I don't get this answer.

I went 10 mL * 1N * 2/1 = 20 mL.

What's the correct way to think about this Q? Thanks!

 

[lifeisgood]

given that following rxn

HCl + Ba(OH)2 --> BaCl2 + H2O. What volume of 1 N of HCK is required to react completely w/ 10 mL of 1 N Ba(OH)2?

the correct answer is 10 mL. But I am not sure why I don't get this answer.

I went 10 mL * 1N * 2/1 = 20 mL.

What's the correct way to think about this Q? Thanks!

Any time you deal with normality you just use N1V1=N2V2...they are telling you to use 1N Ba(OH)2 so naturally it would take an equiv volume of 1N acid to titrate.

 

[Indie]

Any time you deal with normality you just use N1V1=N2V2...they are telling you to use 1N Ba(OH)2 so naturally it would take an equiv volume of 1N acid to titrate.

I think he multiplied by 2, because Ba(oh)2 would give off 2(oh-), so he assumed it was 2N... just a thought

 

[Smooth Operater]

yeah, that's what I though. don't we have to go 2*N1*V1 = N2*V2, given N1 is Ba(OH)2? Thanks

 

[lifeisgood]

yeah, that's what I though. don't we have to go 2*N1*V1 = N2*V2, given N1 is Ba(OH)2? Thanks

but that is WRONG, don't multiply by 2 b/c the tell you Ba(OH)2 is 1N!!!!

 

[cryptozoologist]

given that following rxn

HCl + Ba(OH)2 --> BaCl2 + H2O. What volume of 1 N of HCK is required to react completely w/ 10 mL of 1 N Ba(OH)2?

the correct answer is 10 mL. But I am not sure why I don't get this answer.

I went 10 mL * 1N * 2/1 = 20 mL.

What's the correct way to think about this Q? Thanks!

IF YOU MULTIPLY BY 2, YOU'RE FINDING THE ANSWER FOR MOLARITY, NOT NORMALITY. YOU DO NOT NEED TO CONVERT.