If upright, it is ALWAYS virtual? If upside down, it is ALWAYS real?
if so, this will make life a lot easier lol
here's hoping.
if so, this will make life a lot easier lol
here's hoping.
Yeah, virtual is upright, real is inverted. It deals with the equation
m = -hi/ho = -di/do
wait about in a double lens system where do can be negative and di can be positive.
If upright, it is ALWAYS virtual? If upside down, it is ALWAYS real?
if so, this will make life a lot easier lol
here's hoping.
Thought more about this and it does make it simpler for the MCAT. Any answer choices that are "real and upright" or "virtual and inverted" are wrong!
EK physics #999.
One real image inverted by another converging lens to produce an upright, real image.
its true for a single lens image
once you include another lens it no longer applies to the FINAL image but DOES apply to the intermediate image
ex
converging lens w/ a diverging lens
its true for a single lens image
once you include another lens it no longer applies to the FINAL image but DOES apply to the intermediate image
ex
converging lens w/ a diverging lens
yeah i know this.
So lets make some generalizations:
A converging lens (object outside focal) + diverging lens ---> Inverted, virtual image. Always.
A converging lens (inside focal) + diverging ---> upright virtual
A converging (outside focal) + converging (outside focal) ---> Upright real
A converging (outside focal) + converging (inside focal) ----> i suppose this depends on how close the image is to the second lens. Right?
A converging (inside focal) + converging (outside focal) ---> depends
And converging (inside) + converging (inside) ---> virtual upright.