Is the static friction of a block on an inclined slope the same formula as the kinetic friction of the box moving down the slope?
I was thinking that the static friction would be mgcos(theta) (the normal force). and then the kinetic friction would be the opposite of the direction of the box's movement: -mgsin(theta)
Is this correct? or are they both mgcos(theta)?
For example, if I was looking at work done on the box, would I use sintheta or cos theta?
I was thinking that the static friction would be mgcos(theta) (the normal force). and then the kinetic friction would be the opposite of the direction of the box's movement: -mgsin(theta)
Is this correct? or are they both mgcos(theta)?
For example, if I was looking at work done on the box, would I use sintheta or cos theta?