- Joined
- Oct 3, 2009
- Messages
- 69
- Reaction score
- 0
Given the following circle with center O and inscribed angel of 50 that intercepts the circle at points A and B and tangent lines from A and B that meet at external angle x. Find the measure of angle x.
View attachment Graph.png
Explanation:The measure of the central angle at O is 100, twice that of the inscribed angle of 50, since both angles meet at the same points A and B. The central angle of 50 also divides the circle into two arcs measured from side of AB, 100 and 260. The measure of the external angle x, since it is the result of the meeting of two tangents to the circle, is equal to half the difference of these intercepted arcs: x= 1/2[260-100]= 80
My confusion:
The bolded part..where is 260 from?
View attachment Graph.png
Explanation:The measure of the central angle at O is 100, twice that of the inscribed angle of 50, since both angles meet at the same points A and B. The central angle of 50 also divides the circle into two arcs measured from side of AB, 100 and 260. The measure of the external angle x, since it is the result of the meeting of two tangents to the circle, is equal to half the difference of these intercepted arcs: x= 1/2[260-100]= 80
My confusion:
The bolded part..where is 260 from?