Hi all,
My question is about how light with decreased wavelength (violet) is said to "refract more" than light with increased wavelength (red). The way I understand it, is that decreased wavelength leads to increased n (index of refraction),which in turn leads to decreased angle of refraction. So how is a decreased angle of refraction (less bend from the normal surface) equal to "more refraction" inside the prism?
Thanks for your help.
My question is about how light with decreased wavelength (violet) is said to "refract more" than light with increased wavelength (red). The way I understand it, is that decreased wavelength leads to increased n (index of refraction),which in turn leads to decreased angle of refraction. So how is a decreased angle of refraction (less bend from the normal surface) equal to "more refraction" inside the prism?
Thanks for your help.