If a deer is running at 10 m/s, and can maintain that horizontal velocity when it jumps, how high must it jump in order to clear a horizontal distance of 20 meters?
A. 5 m
B. 10 m
C. 20 m
D. 45 m
Okay, so I've been taught that range = horizontal velocity x time of flight
therefore if the range is 20 meters and horizontal velocity is 10 meters then time of flight is 2 seconds
So why can't I plug 2 seconds into the free fall equation y= 1/2gt^2???
My answer comes out to B
but the right answer is listed as A 5 meters
Can someone please explain why I can't plug my time of flight of 2 seconds into the free fall equation of y=1/2gt^2?
A. 5 m
B. 10 m
C. 20 m
D. 45 m
Okay, so I've been taught that range = horizontal velocity x time of flight
therefore if the range is 20 meters and horizontal velocity is 10 meters then time of flight is 2 seconds
So why can't I plug 2 seconds into the free fall equation y= 1/2gt^2???
My answer comes out to B
but the right answer is listed as A 5 meters
Can someone please explain why I can't plug my time of flight of 2 seconds into the free fall equation of y=1/2gt^2?