This table is of reduction potentials. I chose answer C thinking if you flipped the Pd^2+ half reaction, the reduction potential for Pd would -0.99, which would be the on that is least reduced of the options and most oxidized and thus the best reducing agents. Apparently that's wrong and all the answer key says in regards to C is that Pd is the product of a reduction half rxn with a voltage of +0.99. Why can't we flip that half rxn to get the voltage for Pd? I thought that +0.99 is the voltage to reduce Pd^2+ not Pd as well. The correct answer is A.