TBR Gen chem section 2: atomic theory #44,49 on p.138-139

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Dogfood3140

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Hi all,

For number 44, the answer key says to follow the trend of the first row trantsition metals but if we were to deduce the answer from electronic configuration, how would the reasoing be?

Ag: 5s1 4d10
Pd: 5s2 4d8
Mo: 5s1 4d5
Tc: 5s2 4d5

Using this, I'm thinking it'd be something like Ag>Mo and so on.

For number 49, what's the idea behind adding the first two ionization energies?
I am not really sure what the point of that is.

Thanks

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Do a Google search for "Palladium, Electron configuration" and you will get this:
  1. Kr 4d10
    Palladium, Electron configuration
Both electrons are being pulled from D and not from S so IE is higher. The better way to solve is for sure to use the list from table 1 because the 2nd IE for all the elements 1 period up are listed.
 
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