TBR O-chem chapter 6 question 40 practice exam

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swivelj

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Ok the answer explanation states that we have three acetals since we have 3 anomeric carbons attached to three carbon moeities.

But according to the passage and the picture it seems that N-acetylglucosamine is attached at the amino terminus of the protein. So if its attached to nitrogen it can't be an acetal? According to their answer explanation I would think not as well?

After looking the actual antigen up, this isn't the full polysacharide either. There is a galactose and an N-acteylgalactosamine that's common to all three ABO antigenic determinants.

Was I supposed to interpret the "squiggly" lines as more carbohydrates then protein?


Anyway ... I thought to be an acetal, the carbon involved needs to be attached to two esters, didnt think this would qualify if it was apart of an amide nitrogen, this is why I chose 2 instead of 3.

Feel like I'm missing something here.

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