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Q2) By how much would the potential energy of the television change if a 3m ramp were used to get it up to the platform instead of a 2m ramp?
The answer is stated as (3m - 2m)(100kg)(10m/s2) = 1000J increase.
Isn't this wrong? The ramp LENGTH was extended by 1 m. The actual height from the earth's surface isn't increased by 1m. I found the angle by sin(theta) = 1m/2m (from the original set-up), so theta is 30 degrees. Then to find the new height, I did sin(30)=h(new)/3m = 1.5m. The change in PE is therefore (1.5m - 1.0m)(10m/s2)(100kg) = 500J. Is my reasoning not correct?
Thanks!
The answer is stated as (3m - 2m)(100kg)(10m/s2) = 1000J increase.
Isn't this wrong? The ramp LENGTH was extended by 1 m. The actual height from the earth's surface isn't increased by 1m. I found the angle by sin(theta) = 1m/2m (from the original set-up), so theta is 30 degrees. Then to find the new height, I did sin(30)=h(new)/3m = 1.5m. The change in PE is therefore (1.5m - 1.0m)(10m/s2)(100kg) = 500J. Is my reasoning not correct?
Thanks!