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I have a question about one of the practice exam questions. Question 22 (p.10) on AAMC 3R asks about geometry and dipole moments. While I got the question correct, I want to make certain I understand it. Using the EK method, the geometry of PCl3 is sp2 with a corresponding bond angle of 120 degrees. The image has one of the angles at 107 degrees. Is it because of this difference in angles that creates the dipole moment? Also, would someone please explain why PCl3 is pyramidal and not bent/trigonal planar? Is it simply because of the picture in the question?
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