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One of the discretes in AAMC practice test 7 asks:
Which of the following is most readily prepared by reaction between the corresponding alcohol and concentrated HCl?
two of the answer choices:
Methyl chloride
tert-butyl chloride
I answered methyl chloride, while the actual answer was tert-butyl chloride.
I was under the impression that this substitution would occur via protonation of the alcohol, followed by SN2. I looked it up, and it appears that it can occur via SN1 OR SN2, depending on the substrate.
So what's the rationale for tert-butyl chloride (SN1) over methyl chloride (SN2)?
Which of the following is most readily prepared by reaction between the corresponding alcohol and concentrated HCl?
two of the answer choices:
Methyl chloride
tert-butyl chloride
I answered methyl chloride, while the actual answer was tert-butyl chloride.
I was under the impression that this substitution would occur via protonation of the alcohol, followed by SN2. I looked it up, and it appears that it can occur via SN1 OR SN2, depending on the substrate.
So what's the rationale for tert-butyl chloride (SN1) over methyl chloride (SN2)?