theonlytycrane

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Multiplying .650 L * .120 M = .078 mol, but the CaI2 would dissolve into more mol of solute. Maybe I'm thinking of mol of ions? I thought 'solute' was a bit ambiguous.
 

aldol16

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Multiplying .650 L * .120 M = .078 mol, but the CaI2 would dissolve into more mol of solute. Maybe I'm thinking of mol of ions? I thought 'solute' was a bit ambiguous.
It is ambiguous here. I think it's a subtlety you noticed. The question is correct as written because it's asking for moles of solute and the solute here, i.e. what is being solvated, is CaI2. So there is 0.078 moles of CaI2 but 0.078 moles of Ca2+ and twice that of I- as well.