- Joined
- Aug 19, 2002
- Messages
- 143
- Reaction score
- 0
Ok, for what ever reason, my brain is not working right.
This is from Kaplan's Physical Science Review book on chapter two of physics "Newtonian Mechanics"
M=mass of block A (15)
A=acceleration of block A (2.5)
mk=coefficient of kinetic friction (0.14)
g=acceleration of gravity (9.8)
T=tension of string
Solving for T, from:
MA=T- mkMg
then the book shows:
T=M(mkg+A)
=15(0.14(9.8)+2.5)
=58.1Newtons
My algebra must be way out of practice because I can't recall how each step of this occurred. Can someone break it down detailed step by step algebra for me, from MA=T-mkMg, I'm confused on what to do algebraically with the variable of "M" on each side so that you end up with the equation for T=M(mkg+A)
Thanks in advance.
This is from Kaplan's Physical Science Review book on chapter two of physics "Newtonian Mechanics"
M=mass of block A (15)
A=acceleration of block A (2.5)
mk=coefficient of kinetic friction (0.14)
g=acceleration of gravity (9.8)
T=tension of string
Solving for T, from:
MA=T- mkMg
then the book shows:
T=M(mkg+A)
=15(0.14(9.8)+2.5)
=58.1Newtons
My algebra must be way out of practice because I can't recall how each step of this occurred. Can someone break it down detailed step by step algebra for me, from MA=T-mkMg, I'm confused on what to do algebraically with the variable of "M" on each side so that you end up with the equation for T=M(mkg+A)
Thanks in advance.