The question is:

A 2.0 kg block had dimensions 3 cm x 5 cm x 8 cm. What is its density?

A. 1.67 x 10^-3 kg/m^3

B. 1.67 kg/m^3

C. 167 kg/m^3

D. 1.67 x 10^4 kg/m^3

I just did 3x5x8 and got 120 cm^3. 100 cm = 1 meter, so 120 cm^3 = 1.2 m^3?

From there, d = m/v --> d = 2.0 kg / 1.2 m^3

density = 1.67 kg/m^3, or choice

A 2.0 kg block had dimensions 3 cm x 5 cm x 8 cm. What is its density?

A. 1.67 x 10^-3 kg/m^3

B. 1.67 kg/m^3

C. 167 kg/m^3

D. 1.67 x 10^4 kg/m^3

I just did 3x5x8 and got 120 cm^3. 100 cm = 1 meter, so 120 cm^3 = 1.2 m^3?

From there, d = m/v --> d = 2.0 kg / 1.2 m^3

density = 1.67 kg/m^3, or choice

The book (examkrackers 1001 questions in gchem, page 9, question 108) says the answer is D. Can anyone explain this to me? Something's really wrong with the way I'm approaching this problem most likelyThe book (examkrackers 1001 questions in gchem, page 9, question 108) says the answer is D. Can anyone explain this to me? Something's really wrong with the way I'm approaching this problem most likely

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