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Question: Is benzophenone more soluble in MetOH or Hexane?
Answer: Benzophenone dissolves faster in MetOH than in Hexane.
Benzophenone is a ketone, making it polar, but majorly nonpolar with two phenyl rings.
If we would put these in terms of fractions, I would say that this molecule is 3/4 nonpolar, and 1/4 polar.
So this molecule being majorly nonpolar, why would it be more soluble in MetOH than in Hexane?
Is it because the -OH on MetOH can perform H-bonding with the keto- group?
But wouldn't the dispersion forces be more dominant with the 2 phenyl rings?
Answer: Benzophenone dissolves faster in MetOH than in Hexane.
Benzophenone is a ketone, making it polar, but majorly nonpolar with two phenyl rings.
If we would put these in terms of fractions, I would say that this molecule is 3/4 nonpolar, and 1/4 polar.
So this molecule being majorly nonpolar, why would it be more soluble in MetOH than in Hexane?
Is it because the -OH on MetOH can perform H-bonding with the keto- group?
But wouldn't the dispersion forces be more dominant with the 2 phenyl rings?