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Really having trouble with fluids.
A bathtub duck floats in water with one third of its volume above the water line. What is its specific gravity?
The explanation is that since one third of the duck is shown above the water, the displaced volume is 2/3V.
That means that the volume of displaced water is equal to 2/3 the volume of the duck? So Vwaterdisplaced = 2/3Vduck
Also, since the duck is floating, that means that Fb = mg?
Fb=dVdisplacedg
d=m/v so m=vd so mg = dvg
So dVdisplacedg = dVduckg
vdisplaced = vduck
Since 2/3 of the duck is submerged, the displaced volume = 2/3Vduck.
So the specific gravity of the duck is 2/3? Since the density of water is 1000kg/m^3, does that mean the density of the duck is 667kg/m^3?
I think I understand this problem, and I know it's the most simple fluid problem there is, but I want to be sure I'm not missing any of the important systematic problem solving steps.
Thanks!
A bathtub duck floats in water with one third of its volume above the water line. What is its specific gravity?
The explanation is that since one third of the duck is shown above the water, the displaced volume is 2/3V.
That means that the volume of displaced water is equal to 2/3 the volume of the duck? So Vwaterdisplaced = 2/3Vduck
Also, since the duck is floating, that means that Fb = mg?
Fb=dVdisplacedg
d=m/v so m=vd so mg = dvg
So dVdisplacedg = dVduckg
vdisplaced = vduck
Since 2/3 of the duck is submerged, the displaced volume = 2/3Vduck.
So the specific gravity of the duck is 2/3? Since the density of water is 1000kg/m^3, does that mean the density of the duck is 667kg/m^3?
I think I understand this problem, and I know it's the most simple fluid problem there is, but I want to be sure I'm not missing any of the important systematic problem solving steps.
Thanks!