# Challenging Dynamic Equilibrium Question

#### Spiker

10+ Year Member
So I run into a problem on a test and I am pretty sure i am right

A+B->C+D Fast

D+B->E Slow

K1[A]=K-1[C][D]
[D]=K1/K-1[A]/[C]
K2[D]=E
K2[ K1/K-1[A]/[C]]=E
K [A]/[C]=E

#### bruceleehiiiyaa

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10+ Year Member
So I run into a problem on a test and I am pretty sure i am right

A+B->C+D Fast

D+B->E Slow

K1[A]=K-1[C][D]
[D]=K1/K-1[A]/[C]
K2[D]=E
K2[ K1/K-1[A]/[C]]=E
K [A]/[C]=E

is this kaplan? i had a similar prob too. i dont think those bastards took the reverse K-1 rxn into account, which they should have. if they didnt, that explains how they arrived to their conclusion.

OP
S

#### Spiker

10+ Year Member
is this kaplan? i had a similar prob too. i dont think those bastards took the reverse K-1 rxn into account, which they should have. if they didnt, that explains how they arrived to their conclusion.
LOL yea!! you got good memory

#### ezsanche

10+ Year Member
5+ Year Member
So I run into a problem on a test and I am pretty sure i am right

A+B->C+D Fast

D+B->E Slow

K1[A]=K-1[C][D]
[D]=K1/K-1[A]/[C]
K2[D]=E
K2[ K1/K-1[A]/[C]]=E
K [A]/[C]=E