1. Visit this thread to beta-test StudySchedule.org. StudySchedule is a free nonprofit site that builds dynamic MCAT study schedules unique for your needs and timeline.
Hey, Guest, do you know how much will it cost you to apply to medical school? Check out SDN's Medical School Application Cost Calculator and plan your budget.

Chemical Equilibrium and Coefficients

Discussion in 'MCAT Study Question Q&A' started by somuchwater, Oct 29, 2014.

  1. SDN is made possible through member donations, sponsorships, and our volunteers. Learn about SDN's nonprofit mission.
  1. somuchwater

    somuchwater 2+ Year Member

    53
    9
    Aug 19, 2013
    My question regards chemical equilibrium and reaction quotient.

    I have always understood these to measures of the ratios of concentrations, where the equilibrium constant is the ratio at equilibrium and Q is at other points. What I don't understand (and cannot find the solution for this anywhere online) is why we apply the coefficient as an exponent. It makes perfect sense to me that if the equation is say A --> 2B + C, that the equation should be

    [2B][C] / [A]. However I don't understand why it is written as [2B]^2 [C] / [A]

    For example, if we start with only A, we would get 2Bs and 1 C for every A consumed. This would continue until we hit equilibrium.

    So if we start with 10 As and equilibrium is when we have 5 As... wouldn't the final concentrations be

    (10 B) (5 C) / ( 5 A)

    instead of

    (100 B) ( 5 C ) / (5 A)
     
  2. SDN Members don't see this ad. About the ads.
  3. Cawolf

    Cawolf 2+ Year Member

    3,343
    2,050
    Feb 26, 2013

Share This Page