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Chemistry question

Discussion in 'Pre-Medical - MD' started by NubianPrincess, Feb 24, 2002.

  1. NubianPrincess

    NubianPrincess Perpetually Bored

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    If you dissolve NaCL (which would be insoluble) in cyclohexane, what effect would it have on the freezing point of the cyclohexane?
     
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  3. BUmiken12

    BUmiken12 Senior Member

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    I would guess it would decrease the freezing point because of freezing point depression (colligative property). The NaCl (just like anyother solute) would hinder the cyclohexane from forming it's lattice; therefore, one would need lower temps to freeze it.
     
  4. Sir William Osler

    Sir William Osler Senior Member

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    if it cant dissolve, then i dont believe there's any effect.
     
  5. bentz

    bentz Senior Member

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    I don't think it would have any effect on the freezing point. The two molecules don't mix and thus there's no interaction to break the tendency for the pure molecule to solidify. I believe formula is: Tf=kf*m. if there is no dissolve solute in the solution, you can't find the molality mixture. Then, the freezing point depression is zero. anyone thinks otherwise???
     
  6. NubianPrincess

    NubianPrincess Perpetually Bored

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    Bentz, that makes sense. Thank you, this question was for my lab report.
     
  7. PunkRockDoc

    PunkRockDoc Senior Member

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    NaCl is insoluble in cyclohexane. There would be no effect. Without going into solution, there would be no molecular interaction.
     
  8. Tweetie_bird

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    hey guys!
    I am back from a long "vacation." (more on that later)
    I think that NaCl, although it won't dissolve in cyclohexane, would have an effect on the fp. Reason being is that freezing point is a colligative property, which relies solely on NUMBER of molecules, not TYPE of molecules in a substance. Atleast that is my impression of it.

    Tweetie
     
  9. kutastha

    kutastha 2K Member
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    </font><blockquote><font size="1" face="Verdana, Helvetica, sans-serif">quote:</font><hr /><font size="2" face="Verdana, Helvetica, sans-serif">Originally posted by Tweetie_bird:
    <strong>hey guys!
    Reason being is that freezing point is a colligative property, which relies solely on NUMBER of molecules, not TYPE of molecules in a substance. Atleast that is my impression of it.</strong></font><hr /></blockquote><font size="2" face="Verdana, Helvetica, sans-serif">Yet there are no molecules in the solution. Take a shot glass, put it in a pot of water and and see what temperature the water boils.
     
  10. DarkChild

    DarkChild Senior Member

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    Tweetie - I think melting point elevation/ boiling point depression - hinges on the fact that the introduced compound dissolves into the liquid. Since NaCl isnt going to dissolve in cyclohexane - think about it as dropping a rock into water - does that change the boiling point?
     
  11. Tobtolip

    Tobtolip Member

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    I have to agree with Tweetie Bird, isnt freezing point depression a colligative property?? Which means it depends solely on the number of molecules, not the type etc. Even if NaCl doesnt dissassocate its still a molecule, and your adding more of it;) So I think the freezing point would drop
     
  12. Tobtolip

    Tobtolip Member

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    Wow I didnt think about it like that Dark Angel... hmm. I guess your right, if it doesnt dissolve and then maybe it wouldnt depress the freezing point..
     
  13. KrazyKid

    KrazyKid Junior Member

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    Does anyone know the answer for sure? I thought I knew it, but reading all these replies makes me second guess, so I would really like to know what the answer is for sure...
     
  14. doepug

    doepug Senior Member

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    The freezing point of cyclohexane will drop.

    Some of the other people who posted hit it on the nose... freezing point depression is a colligative issue. NaCl doesn't have to be soluble to drop the freezing point.
     
  15. Hallm_7

    Hallm_7 Senior Member

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    Freezing point depression is a colligative property. A colligative property refers to substances that are IN SOLUTION. Since the solvent is nonpolar, NaCl will not readily dissociate in it and is therefore not in solution. Colligative properties do not apply in this case. There may be VERY insignificant FP depression due to random NaCl molecules floating through the solvent, but it is so miniscule that there is no need to calculate it.
     
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  17. Sm00th13

    Sm00th13 Senior Member

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    In freezing-point depression, if the solute particles interfere with the process of crystal formation the occurs during freezing, the solute particles lower the temperature. There would be some weak type of intermolecular forces between the salt and cyclohexane and decrease fp. Look at it this way, the salt would take up space (b/c the salt would not dissolve and would be larger as opposed as separate ions) where cyclohexane would be, causing some disturbance in crystal formation. Now that I'm reading the previous, collgative properties does deal with solution. Solution is a homogeneous (same phase) as oppose to heterogeneous, which would be the Nacl and cyclohexane. So I agree with the previous post that fp wouldn't change much. :cool: :cool:
     
  18. Tobtolip

    Tobtolip Member

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    Hmm... I now have a new understanding of colligative properties (just when you thought you had general chem down solid)... I say keep more of these questions coming =P Its good MCAT practice I think =P
     
  19. Epi

    Epi Fuzzy Tiger

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    no effect on fp. molecules have to be dissolved in the solution for it to effect fp. think of it on a molecular level, you cool it down, cyclohexane molecules in solution lose energy and want to form an orderly compact solid. If there is nothing in solution to hinder this movement into a solid, then fp will not change.
     
  20. Hallm_7

    Hallm_7 Senior Member

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    I agree with Tobtolip. These Chemistry problems are kinda fun and they're a good review. Keep posting them. :p
     
  21. bentz

    bentz Senior Member

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