</font><blockquote><font size="1" face="Verdana, Helvetica, sans-serif">quote:</font><hr /><font size="2" face="Verdana, Helvetica, sans-serif">Originally posted by Alli Cat:
<strong>USC Premed-- I agree with you.
Blitz-- The only way an alkane will form a precipitate in solution is if it reacts, since alkane solids don't exist at STP. The precipitate formed was not because of a failure of an alkane to dissolve in AgNO3, but because of the alkyl halide reacting with AgNO3. If you think about it, the alkane layer and the aqueous AgNO3 layer wouldn't mix, they'd just form two phases.
esoteric-- HI is much more acidic than HF. Check your Ochem text. This is because I- is much more stable than F-. Both anions form in solution pretty readily, but much more I- is formed (pH of 1M HI > pH of 1M HF) HOWEVER, since the F- is less stable, it is more reactive, which explains the violent reactivity you described.</strong></font><hr /></blockquote><font size="2" face="Verdana, Helvetica, sans-serif">ya, I know. That's why I'm so stupid. it was an easy question <img border="0" title="" alt="[Frown]" src="frown.gif" />