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DAT Destroyer Organic Chem #63 - Constitutional Isomers question
So I know that the formula for getting the number of stereo centers is 2^n with n being the number of chiral carbons.
I know for number 63, that it is 2^2 = 4 - 1 = 3 since its meso.
BUT I am confused as to how to get the correct number of constitutional isomers ?
Is there a math method that we have in which we can use the answer for the number of stereo isomers in order to derive the number of constitutional isomers ? or is there some type of formula to get the number of constitutional isomers or any tricks ?
Thank you for any help !
So I know that the formula for getting the number of stereo centers is 2^n with n being the number of chiral carbons.
I know for number 63, that it is 2^2 = 4 - 1 = 3 since its meso.
BUT I am confused as to how to get the correct number of constitutional isomers ?
Is there a math method that we have in which we can use the answer for the number of stereo isomers in order to derive the number of constitutional isomers ? or is there some type of formula to get the number of constitutional isomers or any tricks ?
Thank you for any help !