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degrees of unsaturation confusion

Discussion in 'DAT Discussions' started by DentalLonghorn2014, Aug 15, 2015.

  1. DentalLonghorn2014

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    Hey y'all!

    So, I'm a little confused with determining the degrees of unsaturation.

    I understand that Carbon will have 10 hydrogens for saturation
    but what about C4H8? You are missing 2 hydrogens. Is that 1 or 2 degrees of unsat?

    If so, what about C4H7N?
    The total saturation is C4H11N because you add an H for every N...but Chad says that it is 2 degrees of unsaturation. How? You have an extra H added to make it 11 H instead of the usual 10.

    I apologize if I sound frantic lol
     
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  3. Lnguyen7

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    You can use this formula to determine the DOU
    DOU = 1/2(2C + 2 + N - H - X)
    X = halogen
    You ignore Oxygen
    For C4H8: DOU = 1/2(2*4 + 2 - 0 - 8 - 0) = 1
    For C4H7N: DOU = 1/2(2*4 + 2 + 1 - 7 - 0) = 2
     
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  4. nornton

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    For C4H8 that will be 1 degree of unsaturation (1 degree = missing 2 hydrogens). For C4H7N you add 1 H for N so the total number of hydrogens would be 11 if it was unsaturated. You have 7 hydrogens so that is 2 degrees of unsaturation (11-7=4 missing hydrogens).
     
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  5. DentalLonghorn2014

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    Thank you very much everyone!
     

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