Dec 11, 2013
1,475
1,079
Status
Pre-Dental
Hey y'all!

So, I'm a little confused with determining the degrees of unsaturation.

I understand that Carbon will have 10 hydrogens for saturation
but what about C4H8? You are missing 2 hydrogens. Is that 1 or 2 degrees of unsat?

If so, what about C4H7N?
The total saturation is C4H11N because you add an H for every N...but Chad says that it is 2 degrees of unsaturation. How? You have an extra H added to make it 11 H instead of the usual 10.

I apologize if I sound frantic lol
 
Jan 9, 2015
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You can use this formula to determine the DOU
DOU = 1/2(2C + 2 + N - H - X)
X = halogen
You ignore Oxygen
For C4H8: DOU = 1/2(2*4 + 2 - 0 - 8 - 0) = 1
For C4H7N: DOU = 1/2(2*4 + 2 + 1 - 7 - 0) = 2
 
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nornton

2+ Year Member
Jul 19, 2015
55
16
Status
Dental Student
Hey y'all!

So, I'm a little confused with determining the degrees of unsaturation.

I understand that Carbon will have 10 hydrogens for saturation
but what about C4H8? You are missing 2 hydrogens. Is that 1 or 2 degrees of unsat?

If so, what about C4H7N?
The total saturation is C4H11N because you add an H for every N...but Chad says that it is 2 degrees of unsaturation. How? You have an extra H added to make it 11 H instead of the usual 10.

I apologize if I sound frantic lol
For C4H8 that will be 1 degree of unsaturation (1 degree = missing 2 hydrogens). For C4H7N you add 1 H for N so the total number of hydrogens would be 11 if it was unsaturated. You have 7 hydrogens so that is 2 degrees of unsaturation (11-7=4 missing hydrogens).
 
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Dec 11, 2013
1,475
1,079
Status
Pre-Dental
Thank you very much everyone!
 
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