Suppose the reaction:
CO(g) + Cl2(g) ---> COCl2 (g)
has an equalibrium constant of 530. What is the equalibrium constant of the reaction.
2CO(g) + 2Cl2(g) ---> 2COCl2 (g)
Answer is 2.81 x 10^5
EK solution says that since everything doubled, means everything was squared in equalibrium expression therefore Keq is squared as well.
I understand the mathematics behind the answer but doesn't this answer suggest that the concentration of reactants and products affects the equilibrium constant? if i recall correctly, keq is independent of [R] and [P], or does this apply only to reactions which are already at equilibrium?
CO(g) + Cl2(g) ---> COCl2 (g)
has an equalibrium constant of 530. What is the equalibrium constant of the reaction.
2CO(g) + 2Cl2(g) ---> 2COCl2 (g)
Answer is 2.81 x 10^5
EK solution says that since everything doubled, means everything was squared in equalibrium expression therefore Keq is squared as well.
I understand the mathematics behind the answer but doesn't this answer suggest that the concentration of reactants and products affects the equilibrium constant? if i recall correctly, keq is independent of [R] and [P], or does this apply only to reactions which are already at equilibrium?