equating ke with gravitational pe ...

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thebillsfan

Unseasoned Veteran
10+ Year Member
so i know if you equate mv^2/2 with GMm/R you get "escape velocity," with R being radius of the earth.

since GMm/R is a measure of energy, could you do some funky thing where the potential energy of an electric field U=vd could be equated to mv^2/2 such that you now have the escape velocity of an electron from a field or something like that?

so i know if you equate mv^2/2 with GMm/R you get "escape velocity," with R being radius of the earth.

since GMm/R is a measure of energy, could you do some funky thing where the potential energy of an electric field U=vd could be equated to mv^2/2 such that you now have the escape velocity of an electron from a field or something like that?

Kqq/r = 1/2mv^2

could you call this the velocity required for the charged particle to leave the field?

could you call this the velocity required for the charged particle to leave the field?

That's the velocity provided by electric force. I think the escape velocity would be different.

anyone know what the escape velocity would be?