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- Jun 16, 2002
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Hey everyone, I have a general chemistry question. It's so basic, I feel embarassed asking, but it's been years since I've done this and I was trying to help somebody else out but got stuck.
So take these three reactions:
1. NaOH (s) ---> NaOH (aq)
2. NaOH (aq) + HCl (aq) ---> NaCl (aq) + H20 (l)
3. NaOH (s) + HCl (aq) --> NaCl (aq) + H20 (l)
Very basic, yes? Now, show that the algebraic sum of the first two equations equals the third. So, wouldn't that be
NaOH(s)+NaOH(aq)+HCl(aq)-->NaOH(aq)+NaCl(aq)+H20(l)
The NaOH(aq) would cancel on both sides, leaving
NaOH (s) + HCl (aq) --> NaCl (aq) + H20 (l), which is the third equation.
Is this correct?
Now, this is the part that's getting me--the question asks to do the same thing, but using the complete ionic equations. So wouldn't this be:
NaOH(s) --> Na+ (aq) + OH- (aq)
Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) --> Na+(aq)+Cl-(aq)+H20(l)
The sum of these would then be
NaOH(s)+Na+ (aq)+ OH-(aq)+ H+(aq)+ Cl-(aq) --> Na+(aq) +OH-(aq) + Na+(aq) + Cl-(aq) + H20 (l)
One Na+(aq) and 0H- (aq) would drop out of each side, but so would the Cl-(aq), leaving
NaOH (s) + H+ (aq) -->Na+(aq) + H20 (l), which is not the complete ionic equation for equation #3.
Am I doing something wrong here?
So take these three reactions:
1. NaOH (s) ---> NaOH (aq)
2. NaOH (aq) + HCl (aq) ---> NaCl (aq) + H20 (l)
3. NaOH (s) + HCl (aq) --> NaCl (aq) + H20 (l)
Very basic, yes? Now, show that the algebraic sum of the first two equations equals the third. So, wouldn't that be
NaOH(s)+NaOH(aq)+HCl(aq)-->NaOH(aq)+NaCl(aq)+H20(l)
The NaOH(aq) would cancel on both sides, leaving
NaOH (s) + HCl (aq) --> NaCl (aq) + H20 (l), which is the third equation.
Is this correct?
Now, this is the part that's getting me--the question asks to do the same thing, but using the complete ionic equations. So wouldn't this be:
NaOH(s) --> Na+ (aq) + OH- (aq)
Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) --> Na+(aq)+Cl-(aq)+H20(l)
The sum of these would then be
NaOH(s)+Na+ (aq)+ OH-(aq)+ H+(aq)+ Cl-(aq) --> Na+(aq) +OH-(aq) + Na+(aq) + Cl-(aq) + H20 (l)
One Na+(aq) and 0H- (aq) would drop out of each side, but so would the Cl-(aq), leaving
NaOH (s) + H+ (aq) -->Na+(aq) + H20 (l), which is not the complete ionic equation for equation #3.
Am I doing something wrong here?