Fluids question help!

[cardioonc]

A SCUBA diver decides to bring a helium (He) balloon along with her on a diving trip to the Red Sea (specific gravity of 1013 at sea level). She takes her balloon down with her to a depth of 10 meters. At this depth, she calculates the surface area of the balloon to be 0.5 m2. What is the force being exerted by the He on the inside surface of the balloon?

A. 50.7 kN
B. 101.3 kN (correct answer)
C. 152.0 kN
D. 202.6 kN

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[PostHaste]

A SCUBA diver decides to bring a helium (He) balloon along with her on a diving trip to the Red Sea (specific gravity of 1013 at sea level). She takes her balloon down with her to a depth of 10 meters. At this depth, she calculates the surface area of the balloon to be 0.5 m2. What is the force being exerted by the He on the inside surface of the balloon?

A. 50.7 kN
B. 101.3 kN (correct answer)
C. 152.0 kN
D. 202.6 kN

1. Pressure = Force/Area --> Force = Pressure * Area (F=PA)
2. Pressure on Balloon = Pressure due to water column + Atmospheric Pressure = prsgh + Patm
3. Specific Gravity = pRedSea/pwater --> prs=SG*pwater
4. F = (prsgh+Patm)A

prs = 1013 kg/m^3
g = 10 m/s^2
h = 10 m
Patm = 1.013x10^5 Pa
A = 0.5 m^2

F=[(1.013x10^3 kg/m^3)(10 m/s^2)(10 m) + (1.013x10^5 Pa)]*[0.5 m^2]
= 2.026x10^5 Pa * 0.5 m^2
= 1.013x10^5 N
= 101300N = 101.3kN

Note: p = rho = density in the above equations