For all the math lovers =)

[LadiiKay]

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take out those graphing calculators, set your minimum and maximum for x and y to 2 (or -2 depending on the side) and graph this:
x^2 + (y - (x^2)^(1/3))^2 = 1

using wolframalpha for help with this one automatically makes you a *itch*ss 😀
it's stupid but I guarantee a smile when you graph it.
I'll be posting the simpler version already in y equal's format tomorrow morning for those of you too lazy to do it yourselves. it took me a little while to get it, but it was a great study break for me and so with that... enjoy m'dears.

 

[addo]

aww thats so sweet of you, fitting for valentines day

 

[h9i9j9]

👍

Happy Valentines Day to you too! 🙂

 

[jeremmed77]

Ha ha, very nice!

 

[bigDee]

y^2 - 2yx^(2/3) = 1 - x^(4/3) - x^2

 

[bigDee]

Do I need to use the quadratic formula? How do you solve for y?

 

[TooMuchResearch]

Does it come to "58008?"

 

[addo]

Does it come to "58008?"

unfortunately no

 

[dbeast]

Totally inappropriate.

This will make more people graph it guaranteed

 

[Pierson5]

Do I need to use the quadratic formula? How do you solve for y?

Curious about this too.

 

[Wiingy]

For everyone else who forgot how to use the graphing function of the graphing calculator:

Cheat
http://www.wolframalpha.com/input/?i=plot+x^2+++(y+-+(x^2)^(1/3))^2+=+1

 

[LadiiKay]

For everyone else who forgot how to use the graphing function of the graphing calculator:

http://www.wolframalpha.com/input/?i=plot+x^2+%2B+%28y+-+%28x^2%29^%281%2F3%29%29^2+%3D+1

wiingy you gave it away! but as promised here's the simpler version:
y1 = (x^2)^(1/3) - (1 - x^2)^(1/2)
y2 = (1 - x^2)^(1/2) + (x^2)^(1/3)
😍

 

[Wiingy]

wiingy you gave it away! but as promised here's the simpler version:
y1 = (x^2)^(1/3) - (1 - x^2)^(1/2)
y2 = (1 - x^2)^(1/2) + (x^2)^(1/3)
😍

Sorry, changed my post so it's clear I was cheating. 🙄

 

[raltima07]

Nice

 

[NeverSurrender]

haha that's pretty cool!

 

[TheMagician17]

Pretty cool!
If you're willing to go through the trouble...

Turn axes off, set scales
xmin = -1.88
xmax= 1.88
ymin = -1.2
ymax = 1.7

y1= abs(x) + sqrt(1-x^2)
y2 = abs(x) - sqrt(1-x^2)

2nd, Draw, Shade, Vars, Y-Vars, Function, Y1 (insert comma here), Vars, Y-Vars, Function, Y2. ENTER

voila~

 

[deleted357625]

did it in my head

 

[TooMuchResearch]

unfortunately no

Then the answer is probably C, and I'm not going to attempt to dig up a graphing calculator.

 

[addo]

Then the answer is probably C, and I'm not going to attempt to dig up a graphing calculator.

a rough plot by hand resulted in what appears to be a heart shaped curve 😕