D Dencology Full Member 10+ Year Member 15+ Year Member Joined Mar 7, 2008 Messages 396 Reaction score 0 Points 0 Pre-Dental Nov 12, 2008 #1 Advertisement - Members don't see this ad guys please see the attachment Attachments Question i posted on SDN.doc Question i posted on SDN.doc 52 KB · Views: 144
R rick4234 New Member 10+ Year Member Joined Nov 3, 2008 Messages 6 Reaction score 0 Points 0 Nov 12, 2008 #2 Dencology said: guys please see the attachment Click to expand... Hi Dencoogy, Here you go, any further questions are welcome 🙂 ! : 1. HCl+H2O--->H+ + Cl- for HCl, {(50g)/(36g/mol)}/0.1L = 50 / (0.1x36) --> unit is mol/L = M (1) so we got a same M for H+ as in (1). [OH-]= 10^-14 / {50 / (0.1x36) } p[OH] = -log[OH] = 14 + log {50 / (0.1x36) } 2. Covalent bond is intramolar force, ony force is London forces(and this is interm. forces) 3. Va/Vb =sqrt (Db/Da), Va=0.5Vb 0.5Vb/Vb = sqrt (Db/Da) 1/4 = Db/Da Da =4 Db Upvote 0 Downvote
Dencology said: guys please see the attachment Click to expand... Hi Dencoogy, Here you go, any further questions are welcome 🙂 ! : 1. HCl+H2O--->H+ + Cl- for HCl, {(50g)/(36g/mol)}/0.1L = 50 / (0.1x36) --> unit is mol/L = M (1) so we got a same M for H+ as in (1). [OH-]= 10^-14 / {50 / (0.1x36) } p[OH] = -log[OH] = 14 + log {50 / (0.1x36) } 2. Covalent bond is intramolar force, ony force is London forces(and this is interm. forces) 3. Va/Vb =sqrt (Db/Da), Va=0.5Vb 0.5Vb/Vb = sqrt (Db/Da) 1/4 = Db/Da Da =4 Db
