I need a bit of help with this one. I've been trying to do this question via Chad's videos method of balancing but having a bit of trouble.
So first we need to balance Chromiums so Cr^3+ will become -> 2Cr^3+
Oxidation state of Cr in Cr2O7^2= will be +6
So 3 electrons will need to be transferred for this reduction.
For Br^- -> BrO3^-, 6 electrons are transferred.
So should it not be +22H^+ 2Cr2O7 + 1Br^- -> 4Cr^3+ 1BrO3^- +11H2O?
Is this one of those questions that can't be done with Chad's shortcut method? Where you have to break it down into half reactions? Or is there a way to do it with the shortcut method, and if so where did I go wrong?
Thanks in advance