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<gchem> can u balance this? (redox rxn)

Discussion in 'DAT Discussions' started by Keroro, Jul 29, 2006.

  1. Keroro

    Keroro Member
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    KMnO4 + NH3 -> KNO3 +MNO2 + KOH + H20



    I KNOW HOW TO BALANCE REDOX RXN
    BUT WHEN I SAW THIS, AND TRIED AT FIRST.. I WAS LIKE.. WHAT THE..



    HOW CAN YOU DIVIDE INTO TWO HAF RXNS AT FIRST?


    CAN ANY EXPERT EXPLAIN THIS STEP BY STEP?

    THANKS A LOT !
     
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  3. DonExodus

    DonExodus Dentist in Virgin Islands
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    Did it on my own, googled my answer to verify :p
    I got 8 KMnO4 + 3 NH3 --> 3 KNO3 + 8 MnO2 + 2 H2O + 5 KOH

    Blatant plagarism from elsewhere yields the explanation Im too lazy to type :p
    Hope this helps,
    Don
     
  4. allstardentist

    allstardentist All-Star
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    yea i think this was in one of kaplan subject test. takes a while.. hopefully they wont have this time-consuming balaning rxn on the test.
     
  5. slayerdeus

    slayerdeus Member
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    there's another way you can do this by substituting different variables for each coefficient, but you have to be very quick and efficient with your algebra skills. on the DAT it probably isn't worth the time.
     
  6. dat_student

    dat_student Junior Member
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    yes I think there is a faster way. Look at the oxidation state of each element and try to balance it that way ;)
     

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