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gen. chem question

Discussion in 'MCAT: Medical College Admissions Test' started by jd star, Aug 5, 2002.

  1. jd star

    jd star Senior Member
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    i know this is a stupid question, but...

    i can't for the life of me figure out how to assign oxidation numbers to a compound... can anyone help me out?

    thanks :)
     
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  3. AlternateSome1

    AlternateSome1 Burnt Out
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    Hmm...don't feel bad, its not that easy. Basically you start with what you know, and work from there. Generally you will know that one compound ALWAYS takes a certain oxidation state...such as Cl -. Then you figure out what possible numbers could fit for the other oxidation state so that they total 0 (or the oxidation state superscript given!). So...AgCl. Maybe you have no idea what silver's oxidation states are, so you start with knowing Cl is -1. Then you determine that you have no overall charge. Therefore, Ag must be +1. I hope this helps at all.

    ~AS1~
     
  4. Mudd

    Mudd Charlatan & Trouble Maker
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    There are two very useful methods.

    First, as a general extention of the first reply, assume certain typical oxidation states for the usual suspects. This can backfire sometimes, so realize there are some notable exceptions. The most electronegative atom in the compound will typically assume its lowest possible oxidation state. The least electronegative atom will assume its highest oxidation state. The reamining atoms are obtained by difference knowing that the sum of the oxidation states is the charge.

    For instance, H2SO4:

    O is the most electronegative, so it gets -2 (it's lowest possible oxidation state). H is least electronegative, so it gets +1 (it's highest possible oxidation state). The overall charge is zero, so by difference, the S is +6.

    2 (+1) + 4 (-2) + S = 0 therefore S = +6

    There is a second, easier method. As usual, I will preface this by saying I am taking this from the Berkeley Review materials and I believe it is their copywrite protected method, because I have never seen it in another textbook. That said:

    Look at every bond an atom makes. For every bond to a more electronegative atom, give it a +1. For every bond to a less electronegative atom, give it a -1. For every bond to the same atom, give it 0. Add these numbers, along with the charge, and you get the atom's oxidation state.

    For instance, consider ethanal (H3CCHO):

    Carbon one has three bonds to H (-1 for each) and one bond to carbon (zero). It has no charge, so it has an oxidation state of -3.

    Carbon two has one bond to hydrogen (at -1), two bonds to oxygen (+1 for each), and one bond to carbon (zero). It too has no charge, so it has an oxidation state of +1.

    The second method works the best, although if you only have a formula, and don't know the exact structure, you can't use this method.
     
  5. lola

    lola Bovine Member
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    this is what i have done and it has always worked. there are rare instances when, for example, H is not +1, but it will be pretty obvious, because it'll be paired up with something you know is always positive. i doubt they'll try to throw you for a loop on the mcat like that though. just have an idea of the anions/cations that are (almost) always the same (e.g. H1+, Na1+, Cl1-, Br1-) etc... and you should be able to figure it out from there. then look at the subscript. If it's Cl2, you know the charge is -2 and that the oxidation number of the other element is +2 if it's a single element, +1 if it's 2 together.
     
  6. jd star

    jd star Senior Member
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    thanks so much.... that helped a lot :)
     

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