How do you figure out n in pipes closed on one end?

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m25

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What is the n in the equation

n(wavelength)=4L for the pipe that is closed in one end, if you are working with its 3rd harmonic?

My kaplan book is saying that n=3, but i thought for pipes closed in one end, n proceeds like 1,3,5... making n=5 the correct number for n for third harmonic.

Is this just a mistake on kaplan's part?

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I think that you are both correct.

The n value has to be odd, but I think n = 3 is still the third harmonic. The naming schema just skips over the second harmonic, fourth harmonic, etc.
 
I think that you are both correct.

The n value has to be odd, but I think n = 3 is still the third harmonic. The naming schema just skips over the second harmonic, fourth harmonic, etc.
Oooh, so you are saying that I got the naming scheme confused, that there is no such thing as second nor fourth harmonic in pipes with one end closed to start with?
 
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