Hi!! Is there an intuitive way to solve for the p and q values when you just have the p^2 or q^2 values? I can do it when the squared values are easy(i.e. 0.36 is .6 squared) but how can you do it when it's a value like .15 or .35? (these are actual values I had to use when I went through an AAMC CBT this morning). Please help... I don't wanna be screwed on the MCAT because of this stupid mathematical ******ation issue of mine.!!!

well 0.15 is just under 0.16 and 0.35 is just under 0.36 so you could estimate those. Might be close enough.

well p^2+2pq+q^2=1; using p^2=.09 and q^2=.49 .09+2pq+.49=1; rearrange so that 2pq=0.42; pq=.21 at least one of the square root values (p or q) should be easy to figure out. After you figure that value out, you can plug it into pq=0.21 and get the other value. q=(0.21/0.3)=0.7; so p = 0.3 and q=0.7 another example 0.36+2pq+0.16=1 2pq=0.48 pq=0.24 p=0.6 (you should be able to tell that square root of 0.36 is 0.6) q=0.4 I doubt they will give you square roots that are hard to derive (square root of 0.6 for example is too difficult to find without a calculator). EDIT: if they gave you 0.15 and 0.35, p+q would not equal 1. Shady. If they do not give you at least one easy to find value then just do what the other poster said and estimate.